X^2+13x-260=0

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Solution for X^2+13x-260=0 equation: 



X^2+13X-260=0

a = 1; b = 13; c = -260;
Δ = b2-4ac
Δ = 132-4·1·(-260)
Δ = 1209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{1209}}{2*1}=\frac{-13-\sqrt{1209}}{2}
$


$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{1209}}{2*1}=\frac{-13+\sqrt{1209}}{2}
$

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